1) To simplity matters, suppose we choose a circle with unit diameter. Now, the (length of the) circumference of a circle lies between the perimeter of any inscribed polygons and that of any circumscribed polygon. Since it’s a simple metter to compute the perimeters of the regular inscribed and circumscribed six-sided polygons, we easily obtain bounds for phi.
2) The ways to get formula abc are with way firstly change the x coefficient to be one. Secondly the constant in the left parts of on equqtion is disappeared. Thirdly the right and left parts of the x coefficient. And finally is the left parts of an equation is changed to be perfect Quadrate.
3) The way to look for the width an area that is limited y = x2 and y = x + 2 are we start to look for the recuced dots of that two similarity. For it, we mush to finish y = x2 and y = x +2. Than we can know the width of an area from it.
4) How to determine the volume is a cone-shaped cone can be thought of as a pyramid to its base a circle. Described in a pyramid with its base up then obtained a pyramid of its circular base. Pyramid with the same volume per one three times in the broad base in the high times. Established so that the formula volume cone cone-shaped volume that is equal to one per three times in the phi-time finger - the finger pad quadratic cone in cone-time high.
5) How to prove it is a triangle of any one of angle same angle because dealing, which is one of the corner
its the same as the other corner in opposed, from three angles that are added (as a line in the amount of one hundred forty degrees delaoan). And three from the corner of the triangle if any results have added one hundred eighty degrees.
6) Determine how it is with the opportunity. So probolitas of the number is twenty-one divided by thirty-six.
8) Since Pythagoras time many different proofs of the Pythagorean theorem have been supplied. In the second edition his book The Pythagorean Proposition, E.S. Loomis has collected and classified 370 demonstrations of this famous theorem. Closely allied to the Pythagorean theorem is the problem of finding integers a,b,c which can represent the legs and hypotenuse of right triangle.
9)The easiest ways to find the amount of two hundred odd numbers the first is we use array aritmetika. With the same formula with a Un of n plus one times in less than b. Where Un is-n to the tribe, a tribe is the first and b is different.
10) How to create a cube that is, for example:
a. We painted areas pad his first, in the form of the square PQRS.
b.On the point P lukislah corner of his corner.
c. With sloping projection square parallelogram PQRS row form, the image field can be completed base PQRS.
d. Finally, the lateral middle segmental Vertical line, point - titikT, U, V, and W can be drawn, and image cubes PQRSTUVW have.
Selasa, 14 April 2009
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